solubility
posted by Anonymous on .
The Ksp of mercury II hydroxide is 3.60 x 10^26. Calculte the solubility of this compound in g/L

...........Hg(OH)2 ==> Hg^2+ + 2OH^
I..........solid.......0........0
C............x........x........2x
E..........solid.......x........2x
x = solubility
Ksp = (Hg^2+)(OH^)^2
Substitute the E line and solve for x = solubility in mols/L, then convert to g/L. 
1.09*10^74

4.86*10^7 is the real answer

Actually both are wrong the answer is 1.69*10 to the power 7. Trust me I got the answer write on sapling

4.86*10^7 is correct. I also go it right on Sapling. x=2.09*10^9 multiply by Molar Mass 234.605

2.08*10^9

4.88*10^7