Posted by **Lynda** on Tuesday, July 16, 2013 at 2:52am.

Force of attraction between two spheres is 3.75 x 10^-5 dyne when the spheres are placed 18 cm apart. What is force of attraction when placed 52 cm apart?

- Math Ratios -
**Reiny**, Tuesday, July 16, 2013 at 8:02am
F = k (1/d^2) , where F is the force, d is the distance between them , and k is a constant

for the given:

3.75x10^-5 = k/18^2

k = .01215

so F = .01215/d^2

when d = 52

F = .01215/2704 = appr 4.50x10^-6

or

F1/F2 = (d2/d1)^2

F1/3.75x10^-5 = 18^2/52^2

F1 = 4.50x10^-6

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