Force of attraction between two spheres is 3.75 x 10?-5 dyne when the spheres are placed 18 cm apart. What is force of attraction when placed 52 cm apartÉ

Force is inversely proportional to square of distance between bodies, hence F/3.75x10^-5=18^2/52^2

F=(18^2x3.75x10^-5)/52^2
=0.46x10^-5 dynes

To find the force of attraction between two spheres when placed 52 cm apart, we can use the formula for gravitational force:

F = G * (m1 * m2) / r^2

In this formula, F represents the force of attraction, G is the gravitational constant (approximately 6.67430 x 10^-8 dyne * cm^2 / g^2), m1 and m2 are the masses of the two spheres, and r is the distance between the centers of the spheres.

Since the problem only gives us the force of attraction and the initial distance, we need to find the masses of the spheres before using the formula.

To do this, we can rearrange the formula as follows:

(m1 * m2) = (F * r^2) / G

Using the given force of attraction (3.75 x 10^-5 dyne) and distance (18 cm), we can substitute the values into the formula:

(m1 * m2) = (3.75 x 10^-5 dyne) * (18 cm)^2 / (6.67430 x 10^-8 dyne * cm^2 / g^2)

Simplifying this equation will give us the product of the masses of the two spheres.

Once we have the product of the masses, we need to find the force of attraction when the spheres are placed 52 cm apart. To do this, we can use the same formula, but with the new distance:

F = G * (m1 * m2) / (52 cm)^2

Now we can substitute the product of the masses we found earlier into this formula and calculate the force of attraction when the spheres are placed 52 cm apart.