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March 29, 2015

March 29, 2015

Posted by **Anonymous** on Monday, July 15, 2013 at 9:52pm.

- algebra -
**mahesh**, Tuesday, July 16, 2013 at 12:52amNo. of $5=bills a, $10 bill=b and $20 bill=c

Then a+b+c=35

5a+10b+20c=370, and

b+c=a+7.

Substituting value of b+c in first eq.,

a+(a+7)=35 or 2a=28 or a=14 and

b+c=35-14=21.

Substituting value of a in second eq., 14x5+10b+20c=370 or 10b+20c=370-70

Or 10b+20c=300 or b+2c=30

Subtract from this the eq. b+c=21 and we get c=30-21=9. thus b=35-14-9=12.

Check:14x5+12x10+9x20=370

70+120+180=370 OK.

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