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March 29, 2017

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When a ball is thrown in the air at 15mps from a height of 1 ft, how long does it take for the ball to hit the ground?

  • Math - ,

    v=u-gt or 0=15-9.81t since final velocity is 0 and ball is going against gravity. Thus t=1.53 sec.

    s=ut-.5gt^2=15-.5x9.81x(1.53)^2
    s=22.95-11.48=121.47 which is the height the ball will go. From there it falls freely for a height of 11.47+1=12.47 ft.
    s=0xt+.5x9.81xt^2 or t=(12.47x2/9.81)=1.59 secs.

  • Math - ,

    PS: s=11.47 which has appeared as 121.47 at one place in 4th line.

  • Math - ,

    since 1 ft = .3 m,

    s(t) = .3 + 15t - 4.9t^2
    it hits the ground when s=0, so

    .3 + 15t - 4.9t^2 = 0
    t = 3.08 sec

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