How many grams of NaOH would be needed to react with 199 g of HCl?

NaOH + HCl --> NaCl + H2O

Paula, ren, Alan, etc. I've shown you how to do two stoichiometry problems. All of these are worked the same way. Limiting reagent stoichiometry problems are slightly different. Refer to your earlier posts.

Mamahuevo

To find out how many grams of NaOH would be needed to react with 199 g of HCl, you need to use stoichiometry, which is a way to balance chemical reactions and relate the amounts of reactants and products.

First, we need to determine the molar masses of NaOH and HCl:
- NaOH: The atomic mass of Na (sodium) is 22.99 g/mol, the atomic mass of O (oxygen) is 16.00 g/mol, and the atomic mass of H (hydrogen) is 1.01 g/mol. Adding these up gives us a molar mass of 22.99 + 16.00 + 1.01 = 39.99 g/mol.
- HCl: The atomic mass of H (hydrogen) is 1.01 g/mol, and the atomic mass of Cl (chlorine) is 35.45 g/mol. Adding these up gives us a molar mass of 1.01 + 35.45 = 36.46 g/mol.

Next, we can use the balanced equation to determine the stoichiometric ratio:
1 mole of NaOH reacts with 1 mole of HCl.

Now, we are ready to calculate the amount of NaOH needed:
1. Convert the mass of HCl to moles using the given molar mass:
moles of HCl = mass of HCl / molar mass of HCl
= 199 g / 36.46 g/mol
≈ 5.46 moles of HCl

2. Since the stoichiometric ratio is 1:1 between NaOH and HCl, the moles of NaOH needed will be equal to the moles of HCl:
moles of NaOH = moles of HCl (from step 1)
≈ 5.46 moles of NaOH

3. Convert moles of NaOH to grams using the molar mass of NaOH:
mass of NaOH = moles of NaOH × molar mass of NaOH
= 5.46 moles × 39.99 g/mol
≈ 218.36 g

Therefore, approximately 218.36 grams of NaOH would be needed to react with 199 grams of HCl.