Posted by **ROBIN** on Monday, July 15, 2013 at 9:01pm.

solve for theda given 0<theda<2pi

cos theta= - (sqrt 3)/ 2

- MATH -
**Steve**, Tuesday, July 16, 2013 at 9:40am
you know that cos π/6 = √3/2

You also know that cos(x) < 0 in QII,QIII

So, ...

- MATH -
**ROBIN**, Tuesday, July 16, 2013 at 10:56pm
so ould it be sin pi.6 and tan pi/6??

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