Posted by **tyneisha** on Monday, July 15, 2013 at 3:37pm.

(4x+y)^2

answer:16x^2+y^2

is this correct?

- alg 2 check? -
**Steve**, Monday, July 15, 2013 at 3:45pm
not quite

(4x+y)(4x+y) = 16x^2 + 4xy + 4xy + y^2

= 16x^2 + 8xy + y^2

You can always check your results by evaluating with numbers. For example, if x=1 and y=2,

(4+2)^2 = 36

16*4+1 = 65

a good sign your result is wrong

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