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September 16, 2014

September 16, 2014

Posted by **Robin** on Monday, July 15, 2013 at 8:49am.

f(x)=(8)/(x^2)−(8)/(x^5)

.

Let F(x) be the antiderivative of f(x) with F(1)=0.

Then F(2) equals ?

- Calculus -
**Steve**, Monday, July 15, 2013 at 10:11amF = ∫ 8/x^2 - 8/x^5 dx

= 8/3 x^3 - 8/6 x^6 + C

Since F(1) = 0,

8/3 x^3 - 4/3 x^6 + C = 0

C = 4/3 - 8/3 = -4/3

F(x) = 8/3 x^3 - 4/3 x^6 - 4/3

F(2) = 8/3 (8) - 4/3 (64) = -64

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