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September 21, 2014

September 21, 2014

Posted by **krishna** on Monday, July 15, 2013 at 7:18am.

- maths -
**MathMate**, Monday, July 15, 2013 at 7:22amTwo trains with speeds s and s+5 km/hr.

Initial distance=340 km

final distance = 30 km

Total distance travelled = 340-30=310 km

Total speed = s+s+5=2s+5

Time = 2 hrs

Form equation equating distance travelled

Time*speed=distance, or

2(2s+5)=310

2s+5=155

2s=150

s=75

Speeds of trains are 75 km/h and 80 km/hr

- maths -
**mahesh**, Monday, July 15, 2013 at 7:37amIf one train has a velocity of V km/h, the other one will have velocity V+5 km/h approaching the first train. Therefore Relative velocity will be V+V+5=2V+5 km/h.

Distance travelled by them in 2 hrs is 340-30=310km which is =2(2V+5)

Thus 4V+10=310 or 4V=300 hence V=75km/h and other train has a velocity of 80km/h.

Check: in 2 hrs they will move 75x2+80x2=150+160=310km =340-30 km. OK.

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