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algebra

posted by on .

Solve the system using elimination
X+3y=5
4x+4y=4 I tried to work this problem and
this is what I came up with.
x+3y=5
x+4y=20
7y=15
y=7/15

and x= (5+y)/4
(5+7/15)/2
2/15
x=2/15

x=2/15, y=7/15 I would like for someone to check to see if it is correct.

  • algebra - ,

    Please see your third line: It should be
    4y-3y=20-5 or y=15, by subtracting first equation from second.
    Now x+3*15=5
    Or x=5-45=-40. Check:-40+4*15=20 by putting values in second equation.
    This -40=15-60=-40 OK.

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