Once made by heating wood in the absence of air, methanol (CH3OH) is now made by reacting carbon monoxide and hydrogen at high pressure:

CO(g)+2H2(g)→CH3OH(l)

How many grams of CH3OH can be made from 40.0g of CO if it all reacts?

mols CO = grams/molar mass.

Using the coefficients in the balanced equation, convert mols CO to mols CH3OH.
Then g CH3OH = mols CH3OH x molar mass CH3OH.

This is a simple stoichiomtry problem (as opposed to a limiting reagent problem) and all of these are worked with these four steps. The first step is to write and balance the equation.

45.7 g

To determine the amount of CH3OH produced from 40.0g of CO, we need to use the stoichiometry of the reaction and the molar masses of the substances involved.

1. Find the molar mass of CO (carbon monoxide) and CH3OH (methanol):
The molar mass of CO = 12.01 g/mol (carbon) + 16.00 g/mol (oxygen) = 28.01 g/mol
The molar mass of CH3OH = 12.01 g/mol (carbon) + (4 X 1.01 g/mol) (hydrogen) + 16.00 g/mol (oxygen) = 32.04 g/mol

2. Set up a conversion factor to convert from grams of CO to moles of CO:
1 mol CO / 28.01 g CO

3. Use the stoichiometric ratio of the balanced equation to convert moles of CO to moles of CH3OH:
1 mol CO : 1 mol CH3OH (from the balanced equation)

4. Set up a conversion factor to convert from moles of CH3OH to grams of CH3OH:
32.04 g CH3OH / 1 mol CH3OH

Now, let's solve the problem:

Step 1: Convert grams of CO to moles of CO:
40.0 g CO x (1 mol CO / 28.01 g CO) = 1.428 moles CO

Step 2: Convert moles of CO to moles of CH3OH:
1.428 moles CO x (1 mol CH3OH / 1 mol CO) = 1.428 moles CH3OH

Step 3: Convert moles of CH3OH to grams of CH3OH:
1.428 moles CH3OH x (32.04 g CH3OH / 1 mol CH3OH) = 45.8 g CH3OH

Therefore, from 40.0g of CO, 45.8g of CH3OH can be produced if it all reacts.

To determine the number of grams of CH3OH that can be made from 40.0g of CO, you need to use stoichiometry. Stoichiometry allows you to relate the amounts of reactants and products in a chemical reaction. In this case, you will use the balanced equation and the molar masses of CO and CH3OH to calculate the answer.

1. Start by writing the balanced equation for the reaction:
CO(g) + 2H2(g) → CH3OH(l)

From the equation, you can see that one mole of CO reacts to produce one mole of CH3OH.

2. Find the molar mass of CO and CH3OH:
The molar mass of CO is 28.01 g/mol.
The molar mass of CH3OH is 32.04 g/mol.

3. Calculate the number of moles of CO:
Using the molar mass of CO, divide the given mass (40.0g) by the molar mass:
Number of moles of CO = 40.0g / 28.01 g/mol = 1.428 mol

4. Determine the number of moles of CH3OH produced:
Since the reaction is 1:1, the number of moles of CH3OH produced will also be 1.428 mol.

5. Calculate the mass of CH3OH produced:
Multiply the number of moles of CH3OH by its molar mass:
Mass of CH3OH = 1.428 mol × 32.04 g/mol = 45.82 g

Therefore, 40.0g of CO can produce 45.82g of CH3OH if it all reacts.