Which is the standard form of a circle with equation x^2 + 4x + y^2 - 6y = 3?
A. (x+2)^2+(y+9)^2=16
B. (x-2)^2+(y-9)^2=3
C. (x+2)^2+(y-3)^=16
D. (x+2)^2+(y-3)^2=3
Nope. Forgot to add the constants to both sides of the equation.
x^2 + 4x + y^2 - 6y = 3
(x^2+4x+4) + (y^2-3y+9) = 3+4+9
(x+2)^2 + (y-3)^2 = 16
(C)