March 29, 2017

Post a New Question

Posted by on .

What is the moment of inertia of an object that rolls without slipping down a 2.00-m-high incline starting from rest, and has a final velocity of 6.00 m/s? Express the moment of inertia as a multiple of MR2, where M is the mass of the object and R is its radius.

  • Physics - ,

    PE=KE=KE(transl) + KE(rot).

    mgh = mv²/2 + I ω²/2=
    = mv²/2 + I v²/2R².

    I= (2R²/v²)(mgh- mv²/2)=
    =mR²(2gh/v² -1) =
    = mR²(2•9.8•2/36 -1)=
    =mR²(1.09-1)=0.09 mR²

  • Physics - ,

    The answer's actually 12.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question