Physics
posted by Justin on .
What is the moment of inertia of an object that rolls without slipping down a 2.00mhigh incline starting from rest, and has a final velocity of 6.00 m/s? Express the moment of inertia as a multiple of MR2, where M is the mass of the object and R is its radius.

PE=KE=KE(transl) + KE(rot).
mgh = mv²/2 + I ω²/2=
= mv²/2 + I v²/2R².
I= (2R²/v²)(mgh mv²/2)=
=mR²(2gh/v² 1) =
= mR²(2•9.8•2/36 1)=
=mR²(1.091)=0.09 mR² 
The answer's actually 12.