Thursday
March 23, 2017

Post a New Question

Posted by on Sunday, July 14, 2013 at 5:05pm.

Suppose you exert a force of 180 N tangential to a 0.280-m-radius 75.0-kg grindstone (a solid disk). (a)What torque is exerted? (b) What is the angular acceleration assuming negligible opposing friction? (c) What is the angular acceleration if there is an opposing frictional force of 20.0 N exerted 1.50 cm from the axis?

  • Physics - , Sunday, July 14, 2013 at 5:18pm

    τ=FR= 180•0.28 = 50.4 N•m
    I=mR²/2 = 75•0.28²/2=2.94 N•m²
    τ=Iε =>
    ε= τ/I = 50.4/2.94 = 17.14 rad/s²
    τ₁=FR-F(fr)r =180•0.28 - 20•0.015 = 50.4 – 0.3 = 50.1 N•m
    ε₁= τ₁/I = 50.1/2.94 = 17.04 rad/s²

  • Physics - , Tuesday, March 14, 2017 at 7:43pm

    sdgfgdfsd

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question