How much faster will neon effuse than krypton, given that the molar mass of krypton is 83.8 grams and that of neon is 20.18 grams?
If you want a ratio that will be
(rate Ne/rate Kr) = sqrt(M2/M1)
Where M2 = molar mass Kr
M1 = molar mass Kr.
To determine how much faster neon will effuse than krypton, we can use Graham's Law of effusion. Graham's Law states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass.
Mathematically, this can be expressed as:
Rate of effusion_(neon) / Rate of effusion_(krypton) = sqrt(Molar mass of krypton / Molar mass of neon)
Plug in the given values:
Rate of effusion_(neon) / Rate of effusion_(krypton) = sqrt(83.8 g / 20.18 g)
Now, we can solve for the ratio of the rates of effusion:
Rate of effusion_(neon) / Rate of effusion_(krypton) = sqrt(4.15)
Taking the square root of 4.15:
Rate of effusion_(neon) / Rate of effusion_(krypton) ≈ 2.04
This means that neon will effuse approximately 2.04 times faster than krypton.