a body travels 200 cm in the first two second and 220 cm in the next 4 seconds.what will be the velocity at the seventh second from the start.
v=u+at or 220/4=200/2+a*1
55=50+a or a=5m/s^2
Again, v=55+5*1=60m/sec at the start of 7th second.
phaltu
To find the velocity at the seventh second from the start, we need to determine the average velocity during the time interval from the 2nd to the 7th second.
Given:
Distance travelled in the first 2 seconds = 200 cm
Distance travelled in the next 4 seconds = 220 cm
First, we need to calculate the average velocity for each time interval:
Average velocity for the first 2 seconds = (Distance travelled in the first 2 seconds) / (Time taken) = 200 cm / 2 sec = 100 cm/sec
Average velocity for the next 4 seconds = (Distance travelled in the next 4 seconds) / (Time taken) = 220 cm / 4 sec = 55 cm/sec
Now, we can calculate the total distance travelled from the start to the end of the 7th second:
Total distance travelled = Distance travelled in the first 2 seconds + Distance travelled in the next 4 seconds
= 200 cm + 220 cm
= 420 cm
Next, we can calculate the total time taken from the start to the end of the 7th second:
Total time taken = Time taken for the first 2 seconds + Time taken for the next 4 seconds
= 2 sec + 4 sec
= 6 sec
Finally, we can calculate the average velocity for the entire duration:
Average velocity = (Total distance travelled) / (Total time taken) = 420 cm / 6 sec = 70 cm/sec
Therefore, the velocity at the seventh second from the start will be 70 cm/sec.