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March 24, 2017

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1. what is the 6th root of 8j^6k^3m^3n?
2. What is the fourth root of 4f^2g^2?

  • Algebra - ,

    (8j^6k^3m^3n)^(1/6)
    = 8^(1/6) j k^(1/2) m^(1/2) m^(1/6)
    = √2 j √k √m n^(1/6)
    = j√(2km) n^(1/6)

    (4f^2 g^2)^(1/4)
    = √2 √f √g
    = √(2fg)

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