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August 1, 2014

August 1, 2014

Posted by **Kim** on Sunday, July 14, 2013 at 3:00am.

2. What is the fourth root of 4f^2g^2?

- Algebra -
**Reiny**, Sunday, July 14, 2013 at 7:12am(8j^6k^3m^3n)^(1/6)

= 8^(1/6) j k^(1/2) m^(1/2) m^(1/6)

= √2 j √k √m n^(1/6)

= j√(2km) n^(1/6)

(4f^2 g^2)^(1/4)

= √2 √f √g

= √(2fg)

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