February 20, 2017

Homework Help: College Physics

Posted by Sammy on Saturday, July 13, 2013 at 2:29pm.

A 7 kg mass hangs on a 10 meter long weightless cord. To the nearest cm, what should the new length of the pendulum be in order that the new frequency be 1.8 times its current value?

The correct answer is 309 but I got 250.

Heres what I did..

(1/2pi)(sqrt g/L2) = (2/2pi)(sqrt g/L1)

1/L2 = 4/L1
4L2 = L1
L2 = L1/4

So 10/4 times 100cm/1m = 225...

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