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College Algebra

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Find all solutions of the equation. Check your solutions in the original equation. (Enter your answers from smallest to largest. Enter NONE in any unused answer blanks.)
16t^2/3 + 40t^1/3 + 25 = 0

  • College Algebra - ,

    let u = t^1/3 so we have

    16u^2 + 40u + 25 = 0
    (4u+5)^2 = 0

    so, 4u+5 = 0
    u = -5/4

    so the only solution is t = -∛(5/4)

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