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August 1, 2014

August 1, 2014

Posted by **Jack** on Saturday, July 13, 2013 at 2:07pm.

16t^2/3 + 40t^1/3 + 25 = 0

- College Algebra -
**Steve**, Saturday, July 13, 2013 at 7:08pmlet u = t^1/3 so we have

16u^2 + 40u + 25 = 0

(4u+5)^2 = 0

so, 4u+5 = 0

u = -5/4

so the only solution is t = -∛(5/4)

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