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April 20, 2014

April 20, 2014

Posted by **Isaac** on Friday, July 12, 2013 at 4:41pm.

-ln(x)+1/x from 'e' to 'infinity' + -1/x from 'e' to 'infinity'.

- Calculus -
**Steve**, Friday, July 12, 2013 at 4:45pmtechnically, it means to evaluate the limit as x->∞, but in practice you can just "substitute" ∞ in for x in the expression.

For example, 1/∞ = 0

e^-∞ = 0

But, ln(∞) = ∞, so that may not help much. It could be that your final value is ∞, or undefined.

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