Post a New Question


posted by .

There is this improper integral problem I've been given. I've completed most of it but still don't understand what I'd get, I don't quite get what it means to go from 'e' to 'infity'. What would I get?

-ln(x)+1/x from 'e' to 'infinity' + -1/x from 'e' to 'infinity'.

  • Calculus -

    technically, it means to evaluate the limit as x->∞, but in practice you can just "substitute" ∞ in for x in the expression.

    For example, 1/∞ = 0
    e^-∞ = 0
    But, ln(∞) = ∞, so that may not help much. It could be that your final value is ∞, or undefined.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question