Calculus
posted by Shan on .
Find the absolute extrema of the function. (Round your answer to three decimal places.)
f(x) = xex2 on [0,2]
Absolute maximum value:
at x =
Absolute minimum value:
at x =

f = xe^x^2
f' = (12x^2) e^x^2
so, where is f' = 0?