Posted by **Anonymous** on Friday, July 12, 2013 at 3:00pm.

Skeletal remains had lost 81% of the C-14 they originally contained. Determine the approximate age of the bones. (Assume the half life of carbon-14 is 5730 years. Round your answer to the nearest whole number.)

yr

- Calculus -
**Steve**, Friday, July 12, 2013 at 3:04pm
since the half-life is 5730 years, the amount left after t years is

a = (1/2)^(t/5730)

If 81% is lost, that leaves a = 0.19, then just solve for t.

Since 1/8 < .19 < 1/4, the answer should be between 2 and 3 half-lives.

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