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December 22, 2014

December 22, 2014

Posted by **Anon** on Friday, July 12, 2013 at 12:50pm.

[(x^-3)-x]/[(x^-2)-1]

- AP Calc. -
**Steve**, Friday, July 12, 2013 at 12:51pmx^3-x = x(x^2-1)

- AP Calc. -
**Anon**, Friday, July 12, 2013 at 12:52pmI don't get it...

- AP Calc. -
**Steve**, Friday, July 12, 2013 at 12:53pmsure you do. factor out x^2-1 top and bottom

- AP Calc. -
**Anon**, Friday, July 12, 2013 at 12:54pmbut don't you have to get rid of the negative exponents somehow..?

- AP Calc. -
**Steve**, Friday, July 12, 2013 at 12:56pmsorry. I missed the negative exponents.

(x^-3 - x)/(x^(-2)-1)

(1 - x^4)/x^3 / (1-x^2)/x^2

(1-x^4)/x^3 * x^2/(1-x^2)

(1-x^2)(1+x^2) / x(1-x^2)

(1+x^2)/x

- AP Calc. -
**Anon**, Friday, July 12, 2013 at 12:58pmHow did you go from the original question to the 1st step?

- AP Calc. -
**Steve**, Friday, July 12, 2013 at 12:59pm1/x^3 - x

over a common denominator of x^3, x = x^4/x^3

- AP Calc. -
**Anon**, Friday, July 12, 2013 at 1:01pmohmygosh.. i'm an idiot.. thank you! you're the bestt!(:

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