[(3/x)-(4/y)]/[(4/x)-(3/y)]

(4x-3y) / (3x-4y)

so?

I'm suppose to simplify it, but I keep getting 3y-4x/4y-3x. Can you please show me how to do it?!

They're the same!

Just multiply top and bottom by -1.

Algebra I, guy, algebra I.

Oops.. thankyou haha

To simplify the given expression, we can start by finding a common denominator for both fractions in the numerator and denominator. The least common denominator (LCD) for the fractions (3/x) and (4/y) is xy.

Let's rewrite the expression with a common denominator:

[(3/x)-(4/y)]/[(4/x)-(3/y)] --> [(3y/xy)-(4x/xy)] / [(4y/xy)-(3x/xy)]

Now, we can combine the fractions in the numerator and denominator:

[(3y-4x)/(xy)] / [(4y-3x)/(xy)]

Since we have the same denominator in both fractions, we can simplify further by multiplying the numerator by the reciprocal of the denominator:

[(3y-4x)/(xy)] * [(xy)/(4y-3x)]

Now, we can cancel out the common factors:

(3y-4x)/(4y-3x)

Thus, the simplified expression is (3y-4x)/(4y-3x).