Post a New Question


posted by .

The radioactive element polonium decays according to the law given below where Q0 is the initial amount and the time t is measured in days.
Q(t) = Q0 ยท 2-(t/140)
If the amount of polonium left after 700 days is 45 mg, what was the initial amount present?

  • Calculus -

    Q0 2^-(700/140) = 45

    Note that 700 days is 5 half-lives
    So, 1/32 of Q0 is left

    Q0 = 32*45 = 1440

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question