(3/2)(1/3+ 1)
(2+7/4)(7/4)(7/4)
---> / that stands for a fraction
(3/2)(1/3+ 1)
(3/2)(4/3) = 12/6 = 2
I'll be glad to check your answer for the second problem.
To solve the given expressions:
1. (3/2)(1/3 + 1)
First, simplify the addition inside the parentheses:
1/3 + 1 = (1/3)(3/3) + (3/3) = 3/9 + 9/9 = 12/9 = 4/3
Now, multiply 4/3 by 3/2:
(3/2)(4/3) = (3*4)/(2*3) = 12/6 = 2
Therefore, (3/2)(1/3 + 1) = 2.
2. (2 + 7/4)(7/4)(7/4)
Start with the addition inside the parentheses:
2 + 7/4 = (2)(4/4) + (7/4) = 8/4 + 7/4 = 15/4
Now, multiply 15/4 by 7/4:
(15/4)(7/4) = (15*7)/(4*4) = 105/16
Finally, multiply 105/16 by 7/4:
(105/16)(7/4) = (105*7)/(16*4) = 735/64
Therefore, (2 + 7/4)(7/4)(7/4) = 735/64.