Friday

August 1, 2014

August 1, 2014

Posted by **C** on Wednesday, July 10, 2013 at 6:23pm.

- Calculus -
**Steve**, Thursday, July 11, 2013 at 10:51amsin(xy)=1+x^3-y^2

cos(xy) (y + xy') = 3x^2 - 2yy'

y cos(xy) + xcos(xy) y' = 3x^2 - 2yy'

(x cos(xy) + 2y) y' = 3x^2 - y cos(xy)

y' = (3x^2 - y cos(xy)) / (x cos(xy) + 2y)

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