Posted by C on Wednesday, July 10, 2013 at 6:23pm.
Solve dy/dx for sin(xy)=1+x^3y^2

Calculus  Steve, Thursday, July 11, 2013 at 10:51am
sin(xy)=1+x^3y^2
cos(xy) (y + xy') = 3x^2  2yy'
y cos(xy) + xcos(xy) y' = 3x^2  2yy'
(x cos(xy) + 2y) y' = 3x^2  y cos(xy)
y' = (3x^2  y cos(xy)) / (x cos(xy) + 2y)