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March 30, 2017

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A 5.00×105-kg subway train is brought to a stop from a speed of
0.500 m/s in 0.400 m by a large spring bumper at the end of its track.
What is the force constant k of the spring?

  • physics - ,

    KE=PE
    mv²/ 2 =kx²/2
    k=m(v/x) ²

  • physics - ,

    mvi^2=kxf
    k=mvi^2 / xf2
    k=(5.00*105)(0.5)^2 / (0.4)
    k=328 N/m

  • physics - ,

    oops, forgot to square my x

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