Posted by Meg on Wednesday, July 10, 2013 at 3:10pm.
Suppose the solubility of PbCl2 (s) 5.6 x 10^2 M. Calculate the ksp

Chemistry  DrBob222, Wednesday, July 10, 2013 at 3:53pm
........PbCl2 ==> Pb^2+ + 2Cl^
I......solid......0........0
C......solid......x........2x
E......solid......x........2x
so x = 5.6E2 and
2x = 2*5.6E2
Plug those into Ksp expression and solve for Ksp.
Ksp = (5.6E2)(2*5.6E2)^2 = ?