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July 31, 2014

July 31, 2014

Posted by **Cara** on Tuesday, July 9, 2013 at 9:49pm.

I keep getting (1/3)pi and can't figure out what I'm doing wrong!

- MATH -
**Reiny**, Tuesday, July 9, 2013 at 11:57pmrotating about the y -axis needs

V = π∫x^2 dy

first equation:

y = x^2

2nd equation:

√x = y

x = y^2

x^2 = y^4

so V = π∫y dy - π∫y^4 dy

= π [ (1/2)y^2 - (1/5)y^5] from y = 0 to 1

= π( 1/2 - 1/5)

= (3/10)π

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