Posted by **Cara** on Tuesday, July 9, 2013 at 9:49pm.

Compute the volume of the solid obtained by rotating the region in the first quadrant encolsed by the graphs of the functions y = x^2 and y = sqrt(x) about the y-axis.

I keep getting (1/3)pi and can't figure out what I'm doing wrong!

## Answer this Question

## Related Questions

- Calculus - This problem set is ridiculously hard. I know how to find the volume ...
- Calculus AB - Consider the region trapped between the graphs of y=9-x^2 and y=11...
- Calculus AB - Consider the region trapped between the graphs of y=9-x^2 and y=11...
- Calculus - 1. Find the volume formed by rotating the region enclosed by x=5y and...
- Calculus AB - Consider the region bounded by the graphs of the equations x=y^2 ...
- Calculus - Let f and g be the functions given by f(x)=1+sin(2x) and g(x)=e^(x/2...
- Calculus - a) Find the volume formed by rotating the region enclosed by x = 6y ...
- Calculus - Find the volume of the solid obtained by rotating the region enclosed...
- Calculus I don't understand - Find the volume of the solid obtained by rotating ...
- Calculus - Find the volume of the solid obtained by rotating the region enclosed...

More Related Questions