A 7.50-kg turkey standing at the top of
Ishpatina Ridge, at 693 m the highest point in
Ontario, weighs 73.5 N [down]. Calculate the
magnitude of the gravitational field strength at
this location.
answer is 9.8N/Kg
the gravitational constant G =6.67•10⁻¹¹ N•m²/kg²,
Earth’s mass is M = 5.97•10²⁴kg,
Earth’s radius is R = 6.378•10⁶ m.
E(g) = F/m = G•m •M/m(R+h)²=
= G•M/(R+h)²=
=6.67•10⁻¹¹•M =
5.97•10²⁴/(6.378•10⁶ +693)² =
=9.8 N/kg
To calculate the magnitude of the gravitational field strength at the location of Ishpatina Ridge, we need to use the formula:
Gravitational Field Strength (g) = Weight (W) / Mass (m)
In this case, the weight of the turkey is given as 73.5 N [down] and the mass is given as 7.50 kg. Plugging these values into the formula, we get:
g = 73.5 N / 7.50 kg
Simplifying this equation, we find:
g = 9.8 N/kg.
Therefore, the magnitude of the gravitational field strength at Ishpatina Ridge is 9.8 N/kg.
To calculate the magnitude of the gravitational field strength at a specific location, we can use the formula:
Gravitational field strength (g) = Weight (W) / Mass (m)
In this case, the weight of the turkey is given as 73.5 N [down] and the mass is 7.50 kg.
To convert the weight to a positive value, we can take its absolute value since the gravitational field strength is always positive. So the weight becomes 73.5 N.
Plugging the values into the formula:
g = 73.5 N / 7.50 kg
Calculating the value using a calculator:
g ≈ 9.8 N/kg
Therefore, the magnitude of the gravitational field strength at the top of Ishpatina Ridge is approximately 9.8 N/kg.