Here's a lower bound solution. You may want to investigate other possibilities.
The number 7 can be partitioned into 3 ascending non-negative integers in 8 ways, namely:
There are 3 permutations of partitions (indicated #) with non-distinct digits and 6 permutations of those with distinct digits for a total of
4*3+4*6=36 permutations of non-negative integers whose sum is 7.
Each of these permutations can make a 3x3 grid as follows by putting a permutation as the first line, then rotate the digits to the left:
We can also make another grid by rotating them to the right, as follows:
This doubles the number of grids for a total of
what about this case, i didnt enumerated it
1 2 4
0 5 2
6 0 1
Hint: you need these:
(1) a,b,c,d are non-negative integers
Try to count how many satisfies these conditions (:
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