Posted by Pia on Monday, July 8, 2013 at 4:17pm.
a ladder 25ft long leans against a wall with its foot on level ground 7ft from the base of the wall. If the foot is pulled away from the wall at the rate 2 ft/s express the distance (y) of the top of the ladder above the ground as a function of the time, t seconds in moving

Maths  Steve, Monday, July 8, 2013 at 4:59pm
x^2 + y^2 = 625
x = 2t
y^2 = 625  4t^2
so,
y = √(6254t^2)

Maths  M. Mubashir Bhatti, Saturday, February 8, 2014 at 4:27am
x^2 + y^2 = 625 (Path. theorem)
x = 7+2t
(7+2t)^2 + y^2 = 625
y^2 = 625 (7+2t)^2
y=√625 (7+2t)^2
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