Tuesday
March 28, 2017

Post a New Question

Posted by on .

A 27-kg girl is bouncing on a trampoline. During a certain interval after leaving the surface of the trampoline, her kinetic energy decreases to 200 J from 480 J. How high does she rise during this interval? Neglect air resistance.

  • physics - ,

    ΔKE= ΔPE
    480-200=mgh
    h=(480-200)/27•9.8 = 1.06 m

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question