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July 26, 2016
Posted by **math** on Monday, July 8, 2013 at 10:11am.

x+y<8

x+t<8

t+y<8

z+t<8

- math -
**Steve**, Monday, July 8, 2013 at 11:00amif t=0, we have

x<8

y<8

z<8

x+y<8

so, 0<x<8, y<8-x, z<8

List them all.

If t=1, change the 8's to 7's in the first 3 conditions.

And so on, up to t=7:

x<1

y<1

z<1

x+y<8

(x,y,z,t) = (0,0,0,7)

Don't see the point of the exercise, but there it is. - math -
**math**, Monday, July 8, 2013 at 11:30amsory a mistake, the corect one problem is find all nonnegative integer solutions of the system

x+y<8

x+Z<8

t+y<8

z+t<8