Thursday
July 31, 2014

Homework Help: Calculus 1

Posted by Leo on Monday, July 8, 2013 at 12:40am.

I'm asked to find max and min of: L(t)=12+2.8sin((2pi/365)(t-80).

I find the derivative as:
L'(t)=(5.6*pi/365)*cos[(2pi/365)(t-80)]

but I get lost afterwards.

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