Posted by **Ronnie** on Monday, July 8, 2013 at 12:19am.

To the nearest tenth, find the perimeter of ABC with vertices A(-2-2), B(0,5) and C(3,-1).

- Math -
**Elena**, Monday, July 8, 2013 at 6:42am
AB=sqrt{(x₂-x₁)²+(y₂-y₁)²} =

=sqrt{(0-(-2))²+(5-(-2)) ²} =

=sqrt(4+49)=7.3

BC = sqrt{(x₃-x₂ )²+(y₃-y₂)²} =

=sqrt{(3-0)²+(-1-5) ²} =

=sqrt(9+36)=6.7

CA = sqrt{(x₁-x₃ )²+(y₁-y₃)²} =

=sqrt{(-2-3)²+(-2+1) ²} =

=sqrt(25+1)=5.1

P=AB+BC+CA = 7.3+6.7+5.1 =14.1

- Math -
**Abdullah**, Tuesday, September 6, 2016 at 10:29pm
19.1 units

AB= 7.3

BC=6.8

CA=5

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