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September 1, 2014

September 1, 2014

Posted by **Robin** on Sunday, July 7, 2013 at 9:25pm.

f(x)=x−7cos(x) on the interval [−ð,ð).

- Calculus -
**MathMate**, Sunday, July 7, 2013 at 10:49pmThink of

f(x)=f1(x)+f2(x)

where

f1(x)=x

f2(x)=-cos(x)

We note that f1(x) is monotonically increasing throughout [-π, π) while

f2(x) is increasing between [-π, 0) and decreasing between [0,π).

Therefore to find the absolute maximum and minimum, we only need to check three locations, x=-π, x=0, and x=π.

f(-π)=-π+7 = 3.86 (approx.)

f(0)=0-7=0-7 = -7

f(π)=π+7 = 10.14 (approx.)

from which you can pick out the absolute maximum and minimum.

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