Posted by **Samantha** on Sunday, July 7, 2013 at 7:15pm.

The sum of 3 numbers is 45. The first number is 4 times the second, while the third is 9 more than the second. Create an equation and solve.

- Math -
**Ms. Sue**, Sunday, July 7, 2013 at 7:18pm
x = 2nd number

4x + x + (x + 9) = 45

6x + 9 = 45

6x = 36

x = 6

- Math -
**Steve**, Sunday, July 7, 2013 at 7:19pm
x+y+z=45

x=4y

z=y+9

4y+y+y+9=45

6y=36

y=6

...

- Math -
**Bosnian**, Sunday, July 7, 2013 at 7:24pm
a = first number

b = second number

c = third number

a = 4 b

c = b + 9

a + b + c = 45

4 b + b + b + 9 = 45

6 b + 9 = 45 Subtract 9 to both sides

6 b + 9 - 9 = 45 - 9

6 b = 36 Divide both sides by 6

6 b / 6 = 36 / 6

b = 6

a = 4 b

a = 4 * 6 = 24

c = b + 9

c = 6 + 9 = 15

First numer 24 , second number 6 , third number 15

a + b + c = 45

24 + 6 + 15 = 45

45 = 45

- Math -
**Samantha**, Sunday, July 7, 2013 at 7:25pm
thank you now i understand , i got the answer but i made a mistake on the equation

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