calculate the de broglie wavelength of He atom at 27 degree celsius & v=2.4*1000
4.99×10^-13
To calculate the de Broglie wavelength of a particle, you can use the following formula:
λ = h / p
where:
λ = de Broglie wavelength
h = Planck's constant (6.62607015 × 10^-34 m^2 kg / s)
p = momentum of the particle
To calculate the momentum (p) of the particle, you can use the following formula:
p = m * v
where:
p = momentum
m = mass of the particle
v = velocity of the particle
In this case, we need to first convert the velocity (v) given in meters per second (m/s) to the proper unit (kg m/s). Since the velocity is given in km/s, we can convert it to m/s by multiplying with 1000.
Given:
Temperature (T) = 27 degree Celsius = 300 K
Velocity (v) = 2.4 * 1000 m/s
To calculate the de Broglie wavelength of a He atom, we need to know the mass of a Helium atom. The atomic mass of Helium (He) is approximately 4 atomic mass units (u) or 6.6464764 × 10^-27 kilograms (kg).
Now, let's calculate the momentum (p) of the He atom:
m = 6.6464764 × 10^-27 kg (mass of a Helium atom)
v = 2.4 * 1000 m/s (velocity of the He atom)
p = m * v
p = (6.6464764 × 10^-27 kg) * (2.4 * 1000 m/s)
After calculating the value of momentum (p), we can substitute it into the de Broglie wavelength formula:
λ = h / p
Now, let's calculate the de Broglie wavelength (λ) of the He atom at 27 degrees Celsius.