Sunday

April 20, 2014

April 20, 2014

Posted by **Nat** on Friday, July 5, 2013 at 11:52pm.

- Chemistry -
**DrBob222**, Saturday, July 6, 2013 at 12:18ampH = -log(H^+)

-3.25 = log(H^+)

Solve for (H^+). I estimated 5E-4 but you need to be more accurate than that.

..........HA ==> H^+ + A^-

I.........0.1.....0.....0

C.........-x.....x.....x

E......-0.1-x....x......x

and you know x = 5E-4 from above (again that is an estimate)

Ka = (H^+)(A^-)/(HA)

Solve for Ka.

Then .....HA ==> H^++ A^-

I........0.01.....0....0

C.........-x.....x......x

E......0.01-x.....x.....x

Substitute the E line into Ka expression along with Ka determined from the first part and solve for x = (H^+), then convert to pH.

- Chemistry -
**Nat**, Saturday, July 6, 2013 at 12:35amOh I see what I did wrong! I got the answer 3.75. Thanks for the help!

**Related Questions**

science - 1. Which of the following is TRUE regarding this situation: Solution A...

Chemistry - Complete this table of values for four aqueous solutions at 25 °C. ...

Chemistry - Complete this table of values for four aqueous solutions at 25 °C. ...

Chemistry - Solution x has a pH of 4.35. Solution y has 10- times high [OH-] ...

chemistry - 1)A solution has a [OH-] of 5.2 x 10-4. What is the [H3O+] in the ...

Chemistry - A) Determine the pH of a 0.98 x 10^-2 mol L solution of hydrocyanic ...

Help Chemistry - Can you please tell me if these are right? Determine the pH for...

Chemistry - A solution that contains 2.047 x 10^-1 M of acid, HA, and 1.808 x 10...

Chemistry - The pH of a solution is 11.30. In order to find the concentration of...

Chemistry - Captain Kirk, of the Starship Enterprise, has been told by his ...