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September 21, 2014

September 21, 2014

Posted by **Robin** on Friday, July 5, 2013 at 6:48pm.

ft/min

Note: See number 25 on pg 268 for a picture of this.

- Calculus -
**Reiny**, Friday, July 5, 2013 at 9:10pm"a rate of 10 cubic feet per minute" ---> dV/dt = 10 ft^3/min

base diameter and height are always equal ---> 2r = h

r = h/2

V = (1/3)πr^2 h

= (1/3)π (h^2/4)(h) = (1/12)π h^3

dV/dt = (1/4)π h^2 dh/dt

when h = 16

10 = (1/4)π(256) dh/dt

dh/dt = 40/(256π) = 5π/32 ft/min

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