Saturday

April 18, 2015

April 18, 2015

Posted by **Monica** on Friday, July 5, 2013 at 6:09pm.

- math -
**Kuai**, Friday, July 5, 2013 at 8:41pmx + x + 13 =460/4

2x + 13 = 115

2x + 13 -13 = 115. -13

2x = 102

2x/2 = 102/2

x = 51

x + 13

= 64

- math -
**Reiny**, Friday, July 5, 2013 at 8:57pmdefine your variables:

let the rate of the the slower car be x mph

then the rate of the faster car is x+13 mph

They both drive for 4 hours

distance covered by slower car = 4x

distance covered by faster car = 4(x+13)

4x + 4(x+13) = 460

8x 408

x = 51

slower car went 51 mph

faster car went 64 mph

**Answer this Question**

**Related Questions**

math - two cars leave the same point at noon. one car travels north and the ...

math - two cars leave the same point at noon. one car travels north and the ...

math - Two cars leave the same point at noon. One car travels North and the ...

Algebra - Two cars start at the same point at Alexandria, verginia, and travel 2...

Algebra - Two cyclists leave towns 240km apart at the same time and travel ...

Algebra - Two cars start at the same point at Alexandria, verginia, and travel ...

Algebra - Two cyclists leave towns apart at the same time and travel toward each...

Algebra - Two cyclists leave towns apart at the same time and travel toward each...

Algebra - Two cyclists leave towns apart at the same time and travel toward each...

Help!...Math... - Two cars leave town going opposite directions. One car is ...