math
posted by Monica on .
Two cars leave at the same time from towns that are 460 miles apart and travel toward each other. They meet after 4 hours. Find the rate of each car if one car travels 13 miles per hour faster than the other.

x + x + 13 =460/4
2x + 13 = 115
2x + 13 13 = 115. 13
2x = 102
2x/2 = 102/2
x = 51
x + 13
= 64 
define your variables:
let the rate of the the slower car be x mph
then the rate of the faster car is x+13 mph
They both drive for 4 hours
distance covered by slower car = 4x
distance covered by faster car = 4(x+13)
4x + 4(x+13) = 460
8x 408
x = 51
slower car went 51 mph
faster car went 64 mph