Posted by Anonymous on .
The distribution of heights of adult American men is approximately normal with a mean of 68 inches and a standard deviation of 2 inches. What percent of mean are at least 72 inches tall?
Thanks!!

math 
Kuai,
z = (x mean)/ sd
z = (7268)/2
z= 4/2= 2
1.9772 = .0228
2.28%