Posted by **lin** on Friday, July 5, 2013 at 8:33am.

In triangle ABC, ∠A=20∘ and ∠B=80∘. Let

D be a point on line segment AB such that

AD=BC. What is the measure (in degrees) of ∠ADC?

- heeeeeeeelp math -
**MathMate**, Friday, July 5, 2013 at 10:51am
Given ΔABC,

A=20°

B=80° =>

C=80°

=> isosceles triangle with base BC=x.

Let E=mid-point of BC, then

ΔAEC is a right triangle right-angled at E

EC=x/2

By definition of cosine,

AC=(x/2)/cos(80°)

=x/(2cos(80°))

Consider ΔADC,

AD=x (given)

AC=x/(2cos(80°)) (from above)

∠DAC=20° (given),

we find DC by cosine rule

DC=sqrt(AD²+AC²-2*AD*AC*cos(20°) )

=sqrt(x²+x/(2cos(80°))-x²cos(80°))

=1.879x (approx.)

∠ ADC can be found by the sine rule:

sin(ADC)=(x/(2cos(80°))*sin(20°)/DC

=sin(20°)/(1-2cos(80°))

∠ADC=asin(sin(20°)/(1-2cos(80°)))

=31.6° approx.

Please check my arithmetic.

## Answer This Question

## Related Questions

- Math (Geometry) - In triangle ABC, ∠A=20∘ and ∠B=80∘. ...
- Math (Geometry) - ABCD is a parallelogram with side lengths AB=15,BC=10 and &#...
- Maths - ABCD is a parallelogram with side lengths AB=15,BC=10 and ∠ADC=75...
- geometry!!! please help me!!!! - ABC is a triangle with ∠ACB=45∘. D ...
- geometry - ABCD is a rectangle. On line segment AB, E is a point such that &#...
- geometry! - ABC is an acute angle triangle with points D and E on BC and AC, ...
- geoMETRY! - ABC is an acute angle triangle with points D and E on BC and AC, ...
- geometry! - ABC is an isosceles triangle with AB=AC, ∠BAC=96∘. D is ...
- simple GEOMETRY!! - In triangle ABC, ∠ABC=30∘,∠ACB=60∘. ...
- geometry(triangle) - Triangle ABC is a right triangle with ∠ABC=90∘...

More Related Questions