Posted by lin on Friday, July 5, 2013 at 8:30am.
A strip of 41 squares is numbered 0,1,2,…,40 from left
to right and a token is placed on the square marked 0. Pinar
rolls a pair of standard six-sided dice and moves the token right a number of squares equal to the total of the dice roll. If Pinar rolls doubles, then she rolls the dice a second time and moves the token in the same manner. If Pinar gets doubles again, she rolls the dice a third time and moves the token in the same manner. If Pinar rolls doubles a third time she simply moves the token to the square marked 36.
The expected value of the square that the token ends on can be expressed as a/b where a and b are coprime positive
integers. What is the value of a+b.
- heeeeeeeeeeelp math - MathMate, Friday, July 5, 2013 at 9:45am
Solve using a probability tree.
First calculate the outcomes with distinct rolls for a sum of P(x)=30/36.
For simplicity, the probability is multiplied by 36 to use integers.
sum=x 36*P(x) x*36*P(x)
3 2 6
4 2 8
5 4 20
6 4 24
7 6 42
8 4 32
9 4 36
10 2 20
11 2 22
Sums of 2 and 12 are always doubles so they do not appear in the table above.
Doubles have a probability of 6/36=1/6, so the above table should be multiplied by (1+1/6) to account for the first double then non-doubles.
Getting doubles twice has a probability of (6/36)², so we multiply the above probabilities by (1+1/6+1/36)=43/36 for all cases except 3 doubles.
3 doubles have a probability of (1/6)³, so the complete table becomes:
sum=x P(x) x*P(x)
3 43/648 43/216
4 43/648 43/162
5 43/324 215/324
6 43/324 43/54
7 43/216 301/216
8 43/324 86/81
9 43/324 43/36
10 43/648 215/324
11 43/648 473/648
36 1/216 1/6
for a sum of probabilities of 1.
Expected value of outcome
- heeeeeeeeeeelp math - Buster, Friday, July 5, 2013 at 1:37pm
^Wrong a+b is < 1000
- heeeeeeeeeeelp math - MathMate, Friday, July 5, 2013 at 3:21pm
The way I interpreted the question is that she does not move at all if she rolls doubles.
After rereading, it looks like that when she rolls doubles, she moves the token before rolling again, and on the third double, she advances it to 36.
If this latter interpretation is correct, it will be necessary to adjust the calculations for the new situation.
Try the same principle as above for the new situation. If you don't get the right answer, post what you've got and we'll take it from there.
- heeeeeeeeeeelp math - tolong, Saturday, July 6, 2013 at 7:55am
even with the latter interpretation i still cannot get a result of a+b<1000. could you try working on it?
- heeeeeeeeeeelp math - 12, Sunday, July 7, 2013 at 10:22am
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