Posted by **Sarah** on Wednesday, July 3, 2013 at 11:28pm.

can you explain how to find the bond order of (σ1s)^2(σ1s*)^2(σ2s)^2(σ2s*)^2(σ2p)^2(π 2p)^4(π 2p*)^2... I know that Bond order = (number of bonding electrons - number of antibonding electrons)/2 but i have no idea what to do..

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