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September 2, 2014

September 2, 2014

Posted by **Maria** on Wednesday, July 3, 2013 at 4:33pm.

Hi, I am stuck on this maths problem. Solve for n: (n+2)!/(n)! =110. I get as far as (n+2)(n+1) = 110. When I multiply it out I get n^2,3n,2 = 110. There is only one example similar to this in my book and it used a quadratic equation to solve it. I feel like that is the next step. I am just unsure of what to do with the 2 I have left over from multiplying out the binomial. I'm really sorry if this doesn't make sense. It's been several years since I had to study mathematics and I am really rusty. Any help is greatly appreciated.

- math -
**Steve**, Wednesday, July 3, 2013 at 5:34pm110 = 2*5*11

So, if n=9, (n+1)(n+2) = 10*11 = 110

Or, algebraically,

n^2+3n+2 = 110

n^2+3n-108 = 0

(n+12)(n-9) = 0

n = 9,-12

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