March 30, 2017

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A gas occupies 560.0 mL at 285 K. To what temperature must the gas be lowered if it is to occupy 250.0 mL? Assume that the pressure remains constant.

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    Assuming the gas is ideal, we use Charles' Law to relate the relationship between Temperature & Volume of gas:
    V1/T1 = V2/T2
    T1 = initial temperature of gas (in K)
    T2 = final temperature of gas (in K)
    V1 = initial volume of gas
    V2 = final volume of gas
    (560)/(285) = V2/(250)
    V2 = (560*250)/285
    V2 = ? (units in mL)

    hope this helps~ :)

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