Posted by **madison** on Wednesday, July 3, 2013 at 1:27am.

A gas occupies 560.0 mL at 285 K. To what temperature must the gas be lowered if it is to occupy 250.0 mL? Assume that the pressure remains constant.

- chemistry -
**Jai**, Wednesday, July 3, 2013 at 7:22am
Assuming the gas is ideal, we use Charles' Law to relate the relationship between Temperature & Volume of gas:

V1/T1 = V2/T2

where:

T1 = initial temperature of gas (in K)

T2 = final temperature of gas (in K)

V1 = initial volume of gas

V2 = final volume of gas

substituting,

(560)/(285) = V2/(250)

V2 = (560*250)/285

V2 = ? (units in mL)

hope this helps~ :)

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