Posted by madison on .
A gas occupies 560.0 mL at 285 K. To what temperature must the gas be lowered if it is to occupy 250.0 mL? Assume that the pressure remains constant.
Assuming the gas is ideal, we use Charles' Law to relate the relationship between Temperature & Volume of gas:
V1/T1 = V2/T2
T1 = initial temperature of gas (in K)
T2 = final temperature of gas (in K)
V1 = initial volume of gas
V2 = final volume of gas
(560)/(285) = V2/(250)
V2 = (560*250)/285
V2 = ? (units in mL)
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